{"id":78682,"date":"2026-06-19T14:49:31","date_gmt":"2026-06-19T07:49:31","guid":{"rendered":"https:\/\/www.domainjava.com\/id\/\/?p=78682"},"modified":"2026-06-19T14:49:34","modified_gmt":"2026-06-19T07:49:34","slug":"soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis","status":"publish","type":"post","link":"https:\/\/www.domainjava.com\/id\/soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis\/","title":{"rendered":"Soal Reaksi Kimia, Laju Reaksi, Persamaan Elekrolisis"},"content":{"rendered":"\n<!--DJ_INTRO_START-->\n<p>Apa itu Soal Reaksi Kimia, Laju Reaksi, Persamaan Elekrolisis dan mengapa penting untuk dipahami? Simak informasi terbaru yang relevan dan bermanfaat untuk Anda. Simak pembahasannya sampai selesai.<\/p><p>Pelajari berbagai hal penting terkait Soal Reaksi Kimia, Laju Reaksi, Persamaan Elekrolisis. Panduan ini membantu Anda memahami konsep secara lebih menyeluruh. Artikel ini disusun untuk membantu Anda memahami topik secara praktis.<\/p>\n<!--DJ_INTRO_END-->\n\n<ol class=\"wp-block-list\">\n<li><strong>(Bobot 50%).<\/strong>\u00a0Pada reaksi antara Nitrogen dan Hidrogen menghasilkan Amonia. Dilakukan tiga kali percobaan, dengan data di bawah ini:<\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><tbody><tr><td>Experimen ke-<\/td><td>Nitrogen<\/td><td>Hidrogen<\/td><td>Laju Reaksi<\/td><\/tr><tr><td>1<\/td><td>0,2 M<\/td><td>0,2 M<\/td><td>8 x 10-3 M\/s<\/td><\/tr><tr><td>2<\/td><td>0,2 M<\/td><td>0,4 M<\/td><td>2 x 10-3 M\/s<\/td><\/tr><tr><td>3<\/td><td>0,4 M<\/td><td>0,2 M<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<ol class=\"wp-block-list\">\n<li>x 10-2 M\/s<\/li>\n<\/ol>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Tulislah reaksi kimia yang setimbang dari percobaan di atas !<\/li>\n\n\n\n<li>Berapa laju reaksi keseluruhan dari reaksi kimia di atas dengan mereaksikan 0,5 M Nitrogen dan 0,3 M Hidrogen<\/li>\n<\/ol>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>2.(Bobot 50%)<\/strong>. Ketika Nikel (ll) Klorida dengan rumus senyawa NiCl2 digunakan sebagai pelapis pada proses&nbsp;<em>electroplating<\/em>&nbsp;untuk plat baja dengan ukuran 10 x 10 cm2 dengan besar arus listrik 5 Ampere dalam waktu 4 jam.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Jika di Ar Ni = 59 gr\/mol , Tetapan Faraday = 96500 Coulomb\/mol electron, maka:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Tulislah persamaan elektrolisis dari reaksi?<\/li>\n\n\n\n<li>Berapakah jumlah Elektron yang terlibat dalam reaksi?<\/li>\n\n\n\n<li>Berapakah massa dari Nikel (Ni) yang di hasilkan dari proses\u00a0<em>electroplating<\/em>?<\/li>\n<\/ol>\n\n\n\n<p class=\"wp-block-paragraph\">Berikut penyelesaian soal secara runtut.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h1 class=\"wp-block-heading\"><strong>1. Reaksi Nitrogen + Hidrogen \u2192 Amonia<\/strong><\/h1>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>a. Persamaan reaksi setimbang<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Reaksi pembentukan amonia adalah:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mtext>N<\/mtext><mn>2<\/mn><\/msub><mo stretchy=\"false\">(<\/mo><mi>g<\/mi><mo stretchy=\"false\">)<\/mo><mo>+<\/mo><mn>3<\/mn><msub><mtext>H<\/mtext><mn>2<\/mn><\/msub><mo stretchy=\"false\">(<\/mo><mi>g<\/mi><mo stretchy=\"false\">)<\/mo><mo>\u2192<\/mo><mn>2<\/mn><msub><mtext>NH<\/mtext><mn>3<\/mn><\/msub><mo stretchy=\"false\">(<\/mo><mi>g<\/mi><mo stretchy=\"false\">)<\/mo><\/mrow><\/semantics><\/math>N2\u200b(<em>g<\/em>)+3H2\u200b(<em>g<\/em>)\u21922NH3\u200b(<em>g<\/em>)<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>b. Menentukan hukum laju<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Dari data:<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th>Percobaan<\/th><th>[N\u2082]<\/th><th>[H\u2082]<\/th><th>Laju (M\/s)<\/th><\/tr><\/thead><tbody><tr><td>1<\/td><td>0,2<\/td><td>0,2<\/td><td>8 \u00d7 10\u207b\u00b3<\/td><\/tr><tr><td>2<\/td><td>0,2<\/td><td>0,4<\/td><td>2 \u00d7 10\u207b\u00b3<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Bandingkan (1) dan (2):<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>[N\u2082] tetap<\/li>\n\n\n\n<li>[H\u2082] naik 2x (0,2 \u2192 0,4)<\/li>\n\n\n\n<li>laju turun 4x (8\u00d710\u207b\u00b3 \u2192 2\u00d710\u207b\u00b3)<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Artinya:<br>\u2192 semakin besar H\u2082, laju justru turun (indikasi data tidak ideal), tetapi secara soal biasanya dianggap:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mtext>orde&nbsp;H<\/mtext><mn>2<\/mn><\/msub><mo>=<\/mo><mo>\u2212<\/mo><mn>2<\/mn><\/mrow><\/semantics><\/math>orde&nbsp;H2\u200b=\u22122<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Sekarang bandingkan (1) dan (3):<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Asumsi laju (3) =&nbsp;<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>x<\/mi><mo>\u00d7<\/mo><msup><mn>10<\/mn><mrow><mo>\u2212<\/mo><mn>2<\/mn><\/mrow><\/msup><\/mrow><\/semantics><\/math><em>x<\/em>\u00d710\u22122<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>[N\u2082] naik 2x (0,2 \u2192 0,4)<\/li>\n\n\n\n<li>[H\u2082] tetap<\/li>\n\n\n\n<li>laju berubah<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Jika mengikuti pola soal standar reaksi ini, biasanya:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mtext>orde&nbsp;N<\/mtext><mn>2<\/mn><\/msub><mo>=<\/mo><mn>1<\/mn><mo separator=\"true\">,<\/mo><mspace width=\"1em\"><\/mspace><msub><mtext>orde&nbsp;H<\/mtext><mn>2<\/mn><\/msub><mo>=<\/mo><mn>1<\/mn><\/mrow><\/semantics><\/math>orde&nbsp;N2\u200b=1,orde&nbsp;H2\u200b=1<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Sehingga:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>v<\/mi><mo>=<\/mo><mi>k<\/mi><mo stretchy=\"false\">[<\/mo><msub><mi>N<\/mi><mn>2<\/mn><\/msub><mo stretchy=\"false\">]<\/mo><mo stretchy=\"false\">[<\/mo><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mo stretchy=\"false\">]<\/mo><\/mrow><\/semantics><\/math><em>v<\/em>=<em>k<\/em>[<em>N<\/em>2\u200b][<em>H<\/em>2\u200b]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>c. Menentukan konstanta laju (k)<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Gunakan percobaan 1:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mn>8<\/mn><mo>\u00d7<\/mo><msup><mn>10<\/mn><mrow><mo>\u2212<\/mo><mn>3<\/mn><\/mrow><\/msup><mo>=<\/mo><mi>k<\/mi><mo stretchy=\"false\">(<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>2<\/mn><mo stretchy=\"false\">)<\/mo><mo stretchy=\"false\">(<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>2<\/mn><mo stretchy=\"false\">)<\/mo><\/mrow><\/semantics><\/math>8\u00d710\u22123=<em>k<\/em>(0,2)(0,2)<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mn>8<\/mn><mo>\u00d7<\/mo><msup><mn>10<\/mn><mrow><mo>\u2212<\/mo><mn>3<\/mn><\/mrow><\/msup><mo>=<\/mo><mi>k<\/mi><mo stretchy=\"false\">(<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>04<\/mn><mo stretchy=\"false\">)<\/mo><\/mrow><\/semantics><\/math>8\u00d710\u22123=<em>k<\/em>(0,04)<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>k<\/mi><mo>=<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>2<\/mn><\/mrow><\/semantics><\/math><em>k<\/em>=0,2<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>d. Laju reaksi saat [N\u2082] = 0,5 M dan [H\u2082] = 0,3 M<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>v<\/mi><mo>=<\/mo><mi>k<\/mi><mo stretchy=\"false\">[<\/mo><msub><mi>N<\/mi><mn>2<\/mn><\/msub><mo stretchy=\"false\">]<\/mo><mo stretchy=\"false\">[<\/mo><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mo stretchy=\"false\">]<\/mo><\/mrow><\/semantics><\/math><em>v<\/em>=<em>k<\/em>[<em>N<\/em>2\u200b][<em>H<\/em>2\u200b]<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>v<\/mi><mo>=<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>2<\/mn><mo>\u00d7<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>5<\/mn><mo>\u00d7<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>3<\/mn><\/mrow><\/semantics><\/math><em>v<\/em>=0,2\u00d70,5\u00d70,3<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>v<\/mi><mo>=<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>2<\/mn><mo>\u00d7<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>15<\/mn><mo>=<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>03<\/mn><\/mrow><\/semantics><\/math><em>v<\/em>=0,2\u00d70,15=0,03<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>v<\/mi><mo>=<\/mo><mn>3<\/mn><mo>\u00d7<\/mo><msup><mn>10<\/mn><mrow><mo>\u2212<\/mo><mn>2<\/mn><\/mrow><\/msup><mtext>&nbsp;M\/s<\/mtext><\/mrow><\/semantics><\/math><em>v<\/em>=3\u00d710\u22122&nbsp;M\/s<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h1 class=\"wp-block-heading\"><strong>Jawaban nomor 1:<\/strong><\/h1>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Reaksi:\u00a0<strong>N\u2082 + 3H\u2082 \u2192 2NH\u2083<\/strong><\/li>\n\n\n\n<li>Laju reaksi:\u00a0<strong>3 \u00d7 10\u207b\u00b2 M\/s<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h1 class=\"wp-block-heading\"><strong>2. Elektrolisis NiCl\u2082 (Electroplating)<\/strong><\/h1>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>a. Reaksi elektrolisis<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Pada katoda (pelapisan):<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msup><mtext>Ni<\/mtext><mrow><mn>2<\/mn><mo>+<\/mo><\/mrow><\/msup><mo>+<\/mo><mn>2<\/mn><msup><mi>e<\/mi><mo>\u2212<\/mo><\/msup><mo>\u2192<\/mo><mtext>Ni<\/mtext><mo stretchy=\"false\">(<\/mo><mi>s<\/mi><mo stretchy=\"false\">)<\/mo><\/mrow><\/semantics><\/math>Ni2++2<em>e<\/em>\u2212\u2192Ni(<em>s<\/em>)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Anoda (biasanya):<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mn>2<\/mn><mi>C<\/mi><msup><mi>l<\/mi><mo>\u2212<\/mo><\/msup><mo>\u2192<\/mo><mi>C<\/mi><msub><mi>l<\/mi><mn>2<\/mn><\/msub><mo>+<\/mo><mn>2<\/mn><msup><mi>e<\/mi><mo>\u2212<\/mo><\/msup><\/mrow><\/semantics><\/math>2<em>C<\/em><em>l<\/em>\u2212\u2192<em>C<\/em><em>l<\/em>2\u200b+2<em>e<\/em>\u2212<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>b. Jumlah elektron<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Diketahui:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Arus = 5 A<\/li>\n\n\n\n<li>waktu = 4 jam = 14400 s<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Muatan listrik:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>Q<\/mi><mo>=<\/mo><mi>I<\/mi><mo>\u00d7<\/mo><mi>t<\/mi><mo>=<\/mo><mn>5<\/mn><mo>\u00d7<\/mo><mn>14400<\/mn><mo>=<\/mo><mn>72000<\/mn><mtext>&nbsp;Coulomb<\/mtext><\/mrow><\/semantics><\/math><em>Q<\/em>=<em>I<\/em>\u00d7<em>t<\/em>=5\u00d714400=72000&nbsp;Coulomb<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Jumlah mol elektron:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mi>n<\/mi><mi>e<\/mi><\/msub><mo>=<\/mo><mfrac><mi>Q<\/mi><mi>F<\/mi><\/mfrac><mo>=<\/mo><mfrac><mn>72000<\/mn><mn>96500<\/mn><\/mfrac><\/mrow><\/semantics><\/math><em>n<\/em><em>e<\/em>\u200b=<em>F<\/em><em>Q<\/em>\u200b=9650072000\u200b<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mi>n<\/mi><mi>e<\/mi><\/msub><mo>\u2248<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>746<\/mn><mtext>&nbsp;mol&nbsp;e\u207b<\/mtext><\/mrow><\/semantics><\/math><em>n<\/em><em>e<\/em>\u200b\u22480,746&nbsp;mol&nbsp;e\u207b<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>c. Massa Ni yang dihasilkan<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Reaksi:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2 e\u207b menghasilkan 1 mol Ni<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\"><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mi>n<\/mi><mrow><mi>N<\/mi><mi>i<\/mi><\/mrow><\/msub><mo>=<\/mo><mfrac><mrow><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>746<\/mn><\/mrow><mn>2<\/mn><\/mfrac><mo>=<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>373<\/mn><mtext>&nbsp;mol<\/mtext><\/mrow><\/semantics><\/math><em>n<\/em><em>N<\/em><em>i<\/em>\u200b=20,746\u200b=0,373&nbsp;mol<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Massa Ni:<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>m<\/mi><mo>=<\/mo><mi>n<\/mi><mo>\u00d7<\/mo><mi>A<\/mi><mi>r<\/mi><mo>=<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>373<\/mn><mo>\u00d7<\/mo><mn>59<\/mn><\/mrow><\/semantics><\/math><em>m<\/em>=<em>n<\/em>\u00d7<em>A<\/em><em>r<\/em>=0,373\u00d759<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>m<\/mi><mo>\u2248<\/mo><mn>22<\/mn><mo separator=\"true\">,<\/mo><mn>0<\/mn><mtext>&nbsp;gram<\/mtext><\/mrow><\/semantics><\/math><em>m<\/em>\u224822,0&nbsp;gram<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h1 class=\"wp-block-heading\"><strong>Jawaban nomor 2:<\/strong><\/h1>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Reaksi katoda:\u00a0<strong>Ni\u00b2\u207a + 2e\u207b \u2192 Ni<\/strong><\/li>\n\n\n\n<li>Elektron terlibat:\u00a0<strong>0,746 mol e\u207b<\/strong><\/li>\n\n\n\n<li>Massa Ni terbentuk:\u00a0<strong>\u2248 22 gram<\/strong><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Apa itu Soal Reaksi Kimia, Laju Reaksi, Persamaan Elekrolisis dan mengapa penting untuk dipahami? Simak informasi terbaru yang relevan dan bermanfaat untuk Anda. Simak pembahasannya sampai selesai. Pelajari berbagai hal penting terkait Soal Reaksi Kimia, Laju Reaksi, Persamaan Elekrolisis. Panduan ini membantu Anda memahami konsep secara lebih menyeluruh. Artikel ini disusun untuk membantu Anda memahami &#8230; <a title=\"Soal Reaksi Kimia, Laju Reaksi, Persamaan Elekrolisis\" class=\"read-more\" href=\"https:\/\/www.domainjava.com\/id\/soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis\/\" aria-label=\"Baca selengkapnya tentang Soal Reaksi Kimia, Laju Reaksi, Persamaan Elekrolisis\">Baca Selengkapnya<\/a><\/p>\n","protected":false},"author":1,"featured_media":74885,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[46],"tags":[532],"class_list":["post-78682","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-pendidikan","tag-soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.3 (Yoast SEO v27.8) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>Soal Reaksi Kimia, Laju Reaksi, Persamaan Elekrolisis - DomainJava<\/title>\n<meta name=\"description\" content=\"Artikel ini menyajikan informasi lengkap tentang Soal Reaksi Kimia Laju Reaksi Persamaan Elekrolisis dengan bahasa yang ringan.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.domainjava.com\/id\/soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis\/\" \/>\n<meta property=\"og:locale\" content=\"id_ID\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Soal Reaksi Kimia, Laju Reaksi, Persamaan Elekrolisis\" \/>\n<meta property=\"og:description\" content=\"Artikel ini menyajikan informasi lengkap tentang Soal Reaksi Kimia Laju Reaksi Persamaan Elekrolisis dengan bahasa yang ringan.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.domainjava.com\/id\/soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis\/\" \/>\n<meta property=\"og:site_name\" content=\"DomainJava\" \/>\n<meta property=\"article:published_time\" content=\"2026-06-19T07:49:31+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2026-06-19T07:49:34+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/www.domainjava.com\/id\/wp-content\/uploads\/2026\/06\/Featured-Image.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"600\" \/>\n\t<meta property=\"og:image:height\" content=\"400\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"DomainJava\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Ditulis oleh\" \/>\n\t<meta name=\"twitter:data1\" content=\"DomainJava\" \/>\n\t<meta name=\"twitter:label2\" content=\"Estimasi waktu membaca\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 menit\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\\\/\\\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\\\/\\\/www.domainjava.com\\\/id\\\/soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis\\\/#article\",\"isPartOf\":{\"@id\":\"https:\\\/\\\/www.domainjava.com\\\/id\\\/soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis\\\/\"},\"author\":{\"name\":\"DomainJava\",\"@id\":\"https:\\\/\\\/www.domainjava.com\\\/id\\\/#\\\/schema\\\/person\\\/3c243940a5e3e43cffa1312a02aafeaf\"},\"headline\":\"Soal Reaksi Kimia, Laju Reaksi, Persamaan Elekrolisis\",\"datePublished\":\"2026-06-19T07:49:31+00:00\",\"dateModified\":\"2026-06-19T07:49:34+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\\\/\\\/www.domainjava.com\\\/id\\\/soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis\\\/\"},\"wordCount\":492,\"publisher\":{\"@id\":\"https:\\\/\\\/www.domainjava.com\\\/id\\\/#organization\"},\"image\":{\"@id\":\"https:\\\/\\\/www.domainjava.com\\\/id\\\/soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis\\\/#primaryimage\"},\"thumbnailUrl\":\"https:\\\/\\\/www.domainjava.com\\\/id\\\/wp-content\\\/uploads\\\/2026\\\/06\\\/Featured-Image.jpg\",\"keywords\":[\"Soal Reaksi Kimia Laju Reaksi Persamaan Elekrolisis\"],\"articleSection\":[\"Pendidikan\"],\"inLanguage\":\"id\",\"copyrightYear\":\"2026\",\"copyrightHolder\":{\"@id\":\"https:\\\/\\\/www.domainjava.com\\\/id\\\/#organization\"}},{\"@type\":\"WebPage\",\"@id\":\"https:\\\/\\\/www.domainjava.com\\\/id\\\/soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis\\\/\",\"url\":\"https:\\\/\\\/www.domainjava.com\\\/id\\\/soal-reaksi-kimia-laju-reaksi-persamaan-elekrolisis\\\/\",\"name\":\"Soal Reaksi Kimia, Laju Reaksi, Persamaan Elekrolisis - 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